算法背后的想法很簡(jiǎn)單：

 決定要在其中繪制模擬時(shí)鐘的窗口的大小。這里的窗口大小是 640 * 640。

因此這個(gè)窗口的中心是 (320,320)作為圓心畫(huà)一個(gè)圓（圓的大小應(yīng)該小于窗口的大�。┈F(xiàn)在我們需要在圓的圓周上有時(shí)針和秒針的標(biāo)記 時(shí)針和秒針的坐標(biāo)可以通過(guò)使用圓參數(shù)方程得到：

由于中心的坐標(biāo)是 (Cx,Cy)因此該點(diǎn)的坐標(biāo)將是

x1=Cx+rCos(θ)

y1= Cy + rsin(θ)

因此，在獲得坐標(biāo)后，我們需要為分鐘和小時(shí)標(biāo)記畫(huà)一條線

對(duì)于時(shí)針的標(biāo)記：我們?nèi)⊥鈭A半徑為：315內(nèi)圈半徑為：275

對(duì)于分針的標(biāo)記：我們?nèi)⊥鈭A的半徑為：315內(nèi)圈為：275

注意：

由于 12 小時(shí)對(duì)應(yīng)于時(shí)針旋轉(zhuǎn) 360 度

因此，一小時(shí)分針應(yīng)旋轉(zhuǎn) 360/12=30 度

 因此角度，時(shí)針會(huì)變化 30 度

每旋轉(zhuǎn) 30 度，我們有 5 分鐘

  因此，每分鐘，分針應(yīng)旋轉(zhuǎn) 30/5=6  度      

 因此，分針的角度會(huì)變化 6 度

 180 度 = π 弧度 因此 θ 度= (θ*π/180) 弧度

接下來(lái)我們需要用系統(tǒng)時(shí)鐘更新我們的時(shí)針、分針和秒針。

代碼如下

#include <iostream>

#include "opencv2/highgui/highgui.hpp"

#include "opencv2/imgproc/imgproc_c.h"

#include "opencv2/imgproc/imgproc.hpp"

#include <stdio.h>

#include <ctime>

#include <sys/timeb.h>

using namespace std;

using namespace cv;

int main()

{

    Mat clk(640, 640, CV_8UC3); //Mat to store clock image

    Mat back_up(640, 640, CV_8UC3); //Mat to store backup image

    Point cent(320, 320);

    Point perim(0, 0);

    int rad = 320;

    float sec_angle, min_angle, hour_angle;

    //Draw second markings

    int s1[60];

    for (int i = 0; i < 60; i++)

        for (int j = 0; j < 2; j++)

            if (j % 2 == 0)

                s1[i][j] = 320 + 295 * cos(6.0 * i * 3.14 / 180);

            else

                s1[i][j] = 320 + 295 * sin(6.0 * i * 3.14 / 180);

    int s2[60];

    for (int i = 0; i < 60; i++)

        for (int j = 0; j < 2; j++)

            if (j % 2 == 0)

                s2[i][j] = 320 + 315 * cos(6.0 * i * 3.14 / 180);

            else

                s2[i][j] = 320 + 315 * sin(6.0 * i * 3.14 / 180);

    for (int i = 0; i < 60; i++) {

        line(clk, Point(s1[i], s1[i]), Point(s2[i], s2[i]), Scalar(0, 255, 0, 0), 1.5, CV_AA, 0);

    }

    //Draw hour markings

    int h1;

    for (int i = 0; i < 12; i++)

        for (int j = 0; j < 2; j++)

            if (j % 2 == 0)

                h1[i][j] = 320 + 275 * cos(30.0 * i * 3.14 / 180);

            else

                h1[i][j] = 320 + 275 * sin(30.0 * i * 3.14 / 180);

    int h2;

    for (int i = 0; i < 12; i++)

        for (int j = 0; j < 2; j++)

            if (j % 2 == 0)

                h2[i][j] = 320 + 315 * cos(30.0 * i * 3.14 / 180);

            else

                h2[i][j] = 320 + 315 * sin(30.0 * i * 3.14 / 180);

    for (int i = 0; i < 12; i++) {

        line(clk, Point(h1[i], h1[i]), Point(h2[i], h2[i]), Scalar(0, 255, 0, 0), 4, CV_AA, 0);

    }

    circle(clk, cent, rad - 5, Scalar(0, 0, 255, 0), 4, CV_AA, 0); //Draw outercircle of clock

    circle(clk, cent, 1, Scalar(0, 255, 0, 0), 5, CV_AA, 0);        //Draw inner circle

    back_up = clk.clone();                                                  // Clone to backup image

    time_t rawtime;

    struct tm timeinfo;

    float second;

    float minute;

    float hour;

    float millisec;

    struct timeb tmb;

    while (1) {

        //Access system time and store it to a local variable

        ftime(&tmb);

        rawtime = tmb.time;

        localtime_s(&timeinfo,&rawtime);

        second = timeinfo.tm_sec;

        minute = timeinfo.tm_min;

        hour = timeinfo.tm_hour;

        millisec = tmb.millitm;

        second = second + millisec / 1000;

        sec_angle = (second * 6) + 270;                     //Convert second to angle

        minute = minute + second / 60;

        min_angle = minute * 6 + 270;                        //Convert minute to angle

        if (hour > 12)hour = hour - 12;

        hour_angle = (hour * 30) + (minute * .5) + 270;  //Convert hour to angle

        if (sec_angle > 360)sec_angle = sec_angle - 360;

        if (min_angle > 360)min_angle = min_angle - 360;

        if (hour_angle > 360)hour_angle = hour_angle - 360;

        //Find out the co-ordinates in the circle perimeter for second and draw the line from center

        perim.x = (int)(cent.x + (rad - 5) * cos(sec_angle * CV_PI / 180.0));

        perim.y = (int)(cent.y + (rad - 5) * sin(sec_angle * CV_PI / 180.0));

        line(clk, cent, perim, Scalar(0, 255, 255, 0), 1.5, CV_AA, 0);

        //Find out the co-ordinates on the circle perimeter for minute and draw the line from center

        perim.x = (int)(cent.x + (rad - 50) * cos(min_angle * CV_PI / 180.0));

        perim.y = (int)(cent.y + (rad - 50) * sin(min_angle * CV_PI / 180.0));

        line(clk, cent, perim, Scalar(0, 255, 255, 0), 4, CV_AA, 0);

        //Find out the co-ordinates on the circle perimeter for hour and draw the line from center

        perim.x = (int)(cent.x + (rad - 75) * cos(hour_angle * CV_PI / 180.0));

        perim.y = (int)(cent.y + (rad - 75) * sin(hour_angle * CV_PI / 180.0));

        line(clk, cent, perim, Scalar(0, 255, 255, 0), 8, CV_AA, 0);

        imshow("Clock", clk);  //Show result in a window

        clk.setTo(0);                // set clk image to zero for next drawing

        clk = back_up.clone();  // Clone the previously drawned markings from back-up image

        char c = waitKey(10);   // Wait for few millisecond and go back to loop.

        if (c == 27)break;

    }

    return 0;

}

效果如圖：